[Solved] You wrote this retry decorator but it does not retry on failure. What is the bug? def retry(func): def wrapper(): for _ in range(3): try: func() except Exception: continue return wrapper | Selenium Python

Selenium Python - Advanced Patterns

You wrote this retry decorator but it does not retry on failure. What is the bug?

def retry(func):
    def wrapper():
        for _ in range(3):
            try:
                func()
            except Exception:
                continue
    return wrapper

AThe decorator is missing the @functools.wraps(func) call

BThe except block should raise the exception instead of continue

CThe loop should be a while loop instead of for loop

DThe function does not return the result or stop retrying on success

Step-by-Step Solution

Solution:

Step 1: Check retry logic
The wrapper calls func() but never returns its result or breaks loop on success.
Step 2: Effect of missing return
Without return, wrapper always completes loop and returns None, so retry never stops on success.
Final Answer:
The function does not return the result or stop retrying on success -> Option D
Quick Check:
Missing return causes always 3 retries even on success [OK]

Quick Trick: Always return on success to stop retries [OK]

Common Mistakes:

Not returning function result inside try
Misusing continue in except block
Ignoring decorator metadata preservation

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More Selenium Python Quizzes

You wrote this retry decorator but it does not retry on failure. What is the bug?

Step 1: Check retry logic

Step 2: Effect of missing return

Final Answer:

Quick Check:

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