[Solved] Identify the error in this code snippet:from openpyxl import load_workbook wb = load_workbook('data.xlsx') sheet = wb['Sheet1'] value = sheet.cell(row=0, column=1).value print(value) | Selenium Python

Selenium Python - Data-Driven Testing

Identify the error in this code snippet:

from openpyxl import load_workbook
wb = load_workbook('data.xlsx')
sheet = wb['Sheet1']
value = sheet.cell(row=0, column=1).value
print(value)

Aload_workbook cannot open .xlsx files

BSheet name should be 'sheet1' lowercase

CRow index starts at 1, not 0

Dcell() method requires string coordinates

Step-by-Step Solution

Solution:

Step 1: Check row and column indexing
openpyxl uses 1-based indexing for rows and columns; row=0 is invalid.
Step 2: Verify sheet access and method usage
Sheet name 'Sheet1' is case-sensitive but usually correct; cell() accepts numeric indices.
Final Answer:
Row index starts at 1, not 0 -> Option C
Quick Check:
Row indexing starts at 1 [OK]

Quick Trick: Row and column indexes start at 1 in openpyxl [OK]

Common Mistakes:

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Identify the error in this code snippet: