Given this custom expected condition class: class ElementHasText: def init(self, locator, text): self.locator = locator self.text = text def call(self, driver): element = driver.find_element(*self.locator) return self.text in element.text What will WebDriverWait(driver, 5).until(ElementHasText((By.ID, 'msg'), 'Success')) do if the element's text is 'Operation Success'?

medium📝 Predict Output Q4 of 15

Selenium Python - Advanced Patterns

Given this custom expected condition class: class ElementHasText: def __init__(self, locator, text): self.locator = locator self.text = text def __call__(self, driver): element = driver.find_element(*self.locator) return self.text in element.text What will WebDriverWait(driver, 5).until(ElementHasText((By.ID, 'msg'), 'Success')) do if the element's text is 'Operation Success'?

ARaise TimeoutException immediately

BWait until the element's text contains 'Success' and then return True

CReturn False without waiting

DRaise NoSuchElementException

Step-by-Step Solution

Solution:

Step 1: Understand the condition logic
The condition checks if 'Success' is in the element's text.
Step 2: Analyze the element's text 'Operation Success'
'Success' is a substring, so condition returns True immediately.
Final Answer:
Wait until the element's text contains 'Success' and then return True -> Option B
Quick Check:
Condition returns True if text found, so wait passes [OK]

Quick Trick: Condition returns True when text is found in element [OK]

Common Mistakes:

Assuming exact match needed instead of substring
Expecting immediate exception if text not found yet
Confusing return False with raising exceptions

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Step 1: Understand the condition logic

Step 2: Analyze the element's text 'Operation Success'

Final Answer:

Quick Check:

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