You need to double click a button only if it is both visible and enabled. Which of the following code snippets correctly implements this check before performing the double click?

hard📝 Application Q8 of 15

Selenium Java - Actions Class

AWebElement btn = driver.findElement(By.id("btn")); new Actions(driver).doubleClick(btn).perform();

BWebElement btn = driver.findElement(By.id("btn")); if(btn.isDisplayed() && btn.isEnabled()) { new Actions(driver).doubleClick(btn).perform(); }

CWebElement btn = driver.findElement(By.id("btn")); if(btn.isEnabled()) { new Actions(driver).doubleClick(btn).perform(); }

DWebElement btn = driver.findElement(By.id("btn")); if(btn.isDisplayed()) { new Actions(driver).doubleClick(btn).perform(); }

Step-by-Step Solution

Solution:

Step 1: Check visibility and enabled state
Use isDisplayed() and isEnabled() to verify the button is interactable.
Step 2: Perform double click only if both true
Wrap the doubleClick action inside the if condition checking both.
Step 3: Execute action
Call perform() to execute the double click.
Final Answer:
WebElement btn = driver.findElement(By.id("btn")); if(btn.isDisplayed() && btn.isEnabled()) { new Actions(driver).doubleClick(btn).perform(); } correctly checks both conditions before double clicking.
Quick Check:
Check visibility and enabled before actions. [OK]

Quick Trick: Check isDisplayed() and isEnabled() before doubleClick [OK]

Common Mistakes:

MISTAKES

Skipping visibility or enabled checks
Calling doubleClick without perform()
Checking only one condition instead of both

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More Selenium Java Quizzes

You need to double click a button only if it is both visible and enabled. Which of the following code snippets correctly implements this check before performing the double click?

Step 1: Check visibility and enabled state

Step 2: Perform double click only if both true

Step 3: Execute action

Final Answer:

Quick Check:

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