[Solved] What will be printed by the following Selenium ... What will be printed by the following Selenium Java code?Object result = driver.executeAsyncScript( "var callback = arguments[arguments.length - 1]; | Selenium Java

Selenium Java - JavaScriptExecutor

What will be printed by the following Selenium Java code?

Object result = driver.executeAsyncScript(
  "var callback = arguments[arguments.length - 1];
  setTimeout(() => callback('finished'), 1500);"
);
System.out.println(result);

Afinished

Bnull

Cundefined

DTimeoutException

Step-by-Step Solution

Solution:

Step 1: Identify callback usage
The script uses callback to return 'finished' after 1.5 seconds.
Step 2: Understand executeAsyncScript behavior
It waits for the callback to be called and returns its argument.
Final Answer:
finished -> Option A
Quick Check:
Callback returns 'finished' after delay [OK]

Quick Trick: Callback argument is the async return value [OK]

Common Mistakes:

Expecting immediate return without waiting
Confusing callback argument position
Assuming exceptions without timeout

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What will be printed by the following Selenium Java code?

Step 1: Identify callback usage

Step 2: Understand `executeAsyncScript` behavior

Final Answer:

Quick Check:

Want More Practice?

What will be printed by the following Selenium Java code?

Step 1: Identify callback usage

Step 2: Understand executeAsyncScript behavior

Final Answer:

Quick Check:

Want More Practice?

Step 2: Understand `executeAsyncScript` behavior