[Solved] What will be the output of the following code snippet?import numpy as np from scipy.sparse import csc_matrix from scipy.sparse.... | SciPy

SciPy - Sparse Linear Algebra

What will be the output of the following code snippet?

import numpy as np
from scipy.sparse import csc_matrix
from scipy.sparse.linalg import splu

A = csc_matrix([[3, 0, 0], [0, 4, 0], [0, 0, 5]])
lu = splu(A)
print(lu.L.toarray())

A[[0. 0. 0.] [0. 0. 0.] [0. 0. 0.]]

B[[1. 0. 0.] [0. 1. 0.] [0. 0. 1.]]

C[[3. 0. 0.] [0. 4. 0.] [0. 0. 5.]]

DError: splu requires a dense matrix

Step-by-Step Solution

Solution:

Step 1: Understand splu factorization output
splu returns L and U matrices where L is lower triangular with unit diagonal (1s on diagonal).
Step 2: Check the matrix A and L
A is diagonal, so L is identity matrix because no elimination is needed.
Final Answer:
[[1. 0. 0.] [0. 1. 0.] [0. 0. 1.]] -> Option B
Quick Check:
L matrix diagonal = 1s for splu [OK]

Quick Trick: L matrix from splu has 1s on diagonal [OK]

Common Mistakes:

Expecting L to be the original matrix
Thinking splu needs dense matrix input
Confusing L with U matrix

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What will be the output of the following code snippet?

Step 1: Understand splu factorization output

Step 2: Check the matrix A and L

Final Answer:

Quick Check:

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