[Solved] What will be the output of the following code snippet? from scipy.optimize import dual_annealing def f(x):... What will be the output of the following code snippet? | SciPy

SciPy - Advanced Optimization

What will be the output of the following code snippet?

from scipy.optimize import dual_annealing

def f(x):
    return (x[0] - 3)**2 + (x[1] + 1)**2

bounds = [(-5, 5), (-5, 5)]
result = dual_annealing(f, bounds)
print(round(result.fun, 2))

A10.00

B0.00

C4.00

DError

Step-by-Step Solution

Solution:

Step 1: Understand the function and bounds
The function f(x) calculates the sum of squares of (x[0]-3) and (x[1]+1). The minimum is at x[0]=3 and x[1]=-1, where the function value is 0.
Step 2: dual_annealing finds the minimum within bounds
The bounds allow x[0]=3 and x[1]=-1. So the optimizer should find the minimum function value close to 0. The print statement rounds the result to 2 decimals.
Final Answer:
0.00 -> Option B
Quick Check:
Minimum value = 0.00 [OK]

Quick Trick: Minimum of squared distance function is zero at target point [OK]

Common Mistakes:

Assuming the minimum is outside bounds
Confusing function value with input values
Expecting an error due to function shape

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What will be the output of the following code snippet?

Step 1: Understand the function and bounds

Step 2: dual_annealing finds the minimum within bounds

Final Answer:

Quick Check:

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