[Solved] What will be the output of the following code snippet?from scipy.sparse.linalg import spilu import numpy as np A = np.array([[4,1],[1,3]]) ilu = spilu(A) print(ilu.solve([1,0])) | SciPy

SciPy - Sparse Linear Algebra

What will be the output of the following code snippet?

from scipy.sparse.linalg import spilu
import numpy as np

A = np.array([[4,1],[1,3]])
ilu = spilu(A)
print(ilu.solve([1,0]))

A[0.25 -0.08333333]

B[1. 0.]

C[0.2 0.1]

DRuntimeError

Step-by-Step Solution

Solution:

Step 1: Understand spilu and solve
spilu computes an incomplete LU factorization; solve applies the factorization to a vector.
Step 2: Calculate ilu.solve([1,0])
spilu requires a sparse matrix input; passing a dense numpy array causes a RuntimeError.
Final Answer:
RuntimeError -> Option D
Quick Check:
spilu fails on dense arrays, causing RuntimeError [OK]

Quick Trick: spilu requires sparse matrix input, dense arrays cause error [OK]

Common Mistakes:

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