Which of the following is the correct syntax to perform erosion using scipy.ndimage on a binary image img with a 3x3 structuring element?

easy📝 Conceptual Q3 of 15

SciPy - Image Processing (scipy.ndimage)

Which of the following is the correct syntax to perform erosion using scipy.ndimage on a binary image img with a 3x3 structuring element?

Ascipy.ndimage.dilate(img, structure=np.ones((3,3)))

Bscipy.ndimage.erosion(img, structure=np.ones((3,3)))

Cscipy.ndimage.morphology.erosion(img, np.ones(3))

Dscipy.ndimage.erode(img, size=3)

Step-by-Step Solution

Solution:

Step 1: Recall scipy erosion function syntax
The correct function is scipy.ndimage.erosion with 'structure' parameter as a 2D array.
Step 2: Check options for correct usage
scipy.ndimage.erosion(img, structure=np.ones((3,3))) uses np.ones((3,3)) correctly; others have wrong function names or parameters.
Final Answer:
scipy.ndimage.erosion(img, structure=np.ones((3,3))) -> Option B
Quick Check:
Correct erosion syntax = scipy.ndimage.erosion(img, structure=np.ones((3,3))) [OK]

Quick Trick: Use scipy.ndimage.erosion with 2D structuring element [OK]

Common Mistakes:

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