[Solved] What will be the output of this code snippet? from scipy.cluster.hierarchy import linkage, fcluster import numpy as np X = np.... What will be the output of this code snippet? | SciPy

SciPy - Clustering and Distance

What will be the output of this code snippet?

from scipy.cluster.hierarchy import linkage, fcluster
import numpy as np
X = np.array([[1, 2], [1, 4], [5, 2], [5, 4]])
Z = linkage(X, 'single')
clusters = fcluster(Z, t=3, criterion='distance')
print(clusters)

A[1 1 1 1]

B[1 2 3 4]

C[2 2 1 1]

D[1 1 2 2]

Step-by-Step Solution

Solution:

Step 1: Perform linkage with single method
Linkage merges closest points first. Points [1,2] and [1,4] cluster together, and [5,2] and [5,4] cluster together.
Step 2: Apply fcluster with threshold 3
Distance threshold 3 separates these two clusters, so points 0 and 1 get cluster 1, points 2 and 3 get cluster 2.
Final Answer:
[1 1 2 2] -> Option D
Quick Check:
Cluster labels = [1 1 2 2] [OK]

Quick Trick: Threshold t splits clusters by max distance [OK]

Common Mistakes:

Assuming all points in one cluster
Misunderstanding linkage method effect
Confusing cluster labels order

Master "Clustering and Distance" in SciPy

9 interactive learning modes - each teaches the same concept differently

Learn Why Deep Visual Try Challenge Project Recall Time

More SciPy Quizzes

What will be the output of this code snippet?

Step 1: Perform linkage with single method

Step 2: Apply fcluster with threshold 3

Final Answer:

Quick Check:

Want More Practice?