[Solved] What does this code print?from scipy import optimize f = lambda x: (x - 3)**2 result = optimize.minimize(f, 0) print(round(result.x[0], 2)) | SciPy

SciPy - Basics and Scientific Computing

What does this code print?

from scipy import optimize
f = lambda x: (x - 3)**2
result = optimize.minimize(f, 0)
print(round(result.x[0], 2))

A0.00

B3.00

C-3.00

D1.50

Step-by-Step Solution

Solution:

Step 1: Understand the function and minimization
The function (x-3)^2 has its minimum at x=3.
Step 2: Check the minimize result
The optimizer starts at 0 and finds minimum at 3, printed rounded to 2 decimals.
Final Answer:
3.00 -> Option B
Quick Check:
Minimum of (x-3)^2 is at x=3 [OK]

Quick Trick: Minimize (x-3)^2 -> minimum at 3 [OK]

Common Mistakes:

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