You want to calculate the energy of a photon with frequency 5e14 Hz using Planck's constant from scipy.constants. Which code correctly computes this energy in joules?
hard📝 Application Q8 of 15
SciPy - Constants and Special Functions
You want to calculate the energy of a photon with frequency 5e14 Hz using Planck's constant from scipy.constants. Which code correctly computes this energy in joules?
Aimport scipy.constants as sc
energy = sc.Planck_constant * 5e14
print(energy)
Bfrom scipy.constants import Planck_constant as h
energy = h * 5e14
print(energy)
Cfrom scipy.constants import H
energy = H * 5e14
print(energy)
Dimport scipy.constants as sc
energy = sc.h * 5e14
print(energy)
Step-by-Step Solution
Solution:
Step 1: Identify the correct constant name for Planck's constant
In scipy.constants, Planck's constant is named h.
Step 2: Use the correct import and multiplication
import scipy.constants as sc
energy = sc.h * 5e14
print(energy) uses sc.h multiplied by frequency correctly.
Final Answer:
import scipy.constants as sc
energy = sc.h * 5e14
print(energy) -> Option D
Quick Check:
Correct constant name and usage = import scipy.constants as sc
energy = sc.h * 5e14
print(energy) [OK]
Quick Trick:Use 'h' for Planck's constant in scipy.constants [OK]
Common Mistakes:
MISTAKES
Using Planck_constant instead of h
Incorrect import statements
Confusing variable names
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