[Solved] What will be the output of this code snippet?import scipy.constants as sc speed = sc.speed_of_light print(round(speed, 2)) | SciPy

SciPy - Constants and Special Functions

What will be the output of this code snippet?

import scipy.constants as sc
speed = sc.speed_of_light
print(round(speed, 2))

A299792.46

B3.00e8

C299792458.0

D299792458

Step-by-Step Solution

Solution:

Step 1: Understand the value of speed_of_light in scipy.constants
It is 299792458.0 meters per second (a float).
Step 2: Applying round with 2 decimals
round(299792458.0, 2) returns 299792458.0, which prints as 299792458.0.
Final Answer:
299792458.0 -> Option C
Quick Check:
Rounded speed_of_light = 299792458.0 [OK]

Quick Trick: round() adds decimals even if zero [OK]

Common Mistakes:

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