[Solved] You have a 3x3 matrix:M = np.array([[1, 2, 3], [0, 1, 4], [5, 6, 0]])Using scipy.linalg.det, what is the determinant of M? Choose the closest value rounded to 2 decimals. | SciPy

SciPy - Linear Algebra (scipy.linalg)

You have a 3x3 matrix:

M = np.array([[1, 2, 3], [0, 1, 4], [5, 6, 0]])

Using scipy.linalg.det, what is the determinant of M? Choose the closest value rounded to 2 decimals.

A-24.00

B31.00

C1.00

D-79.00

Step-by-Step Solution

Solution:

Step 1: Calculate determinant manually
Calculate determinant of M:
det(M) = 1*(1*0 - 4*6) - 2*(0*0 - 4*5) + 3*(0*6 - 1*5)
= 1*(0 - 24) - 2*(0 - 20) + 3*(0 - 5)
= -24 + 40 - 15 = 1
Step 2: Confirm with scipy.linalg.det
Using det(M) in code returns 1.0, rounded to 2 decimals is 1.00.
Final Answer:
1.00 -> Option C
Quick Check:
Determinant = 1.00 [OK]

Quick Trick: Use cofactor expansion for 3x3 determinant [OK]

Common Mistakes:

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