[Solved] Examine this Ruby code snippet:mutex = Mutex.new counter = 0 threads = 4.times.map do Thread.new do 25.times do mutex.synchronize { counter += 1 } end end end threads.... | Ruby

Ruby - Concurrent Programming

Examine this Ruby code snippet:

mutex = Mutex.new
counter = 0
threads = 4.times.map do
  Thread.new do
    25.times do
      mutex.synchronize { counter += 1 }
    end
  end
end
threads.each(&:join)
puts counter

What issue might still arise despite using a Mutex here?

AThe code will raise an exception due to improper Mutex usage.

BThe counter variable is not thread-safe even with Mutex.

CThreads may deadlock because Mutex is not released.

DNo issue; the Mutex correctly prevents race conditions.

Step-by-Step Solution

Solution:

Step 1: Analyze Mutex usage
The code uses mutex.synchronize to protect increments to counter.
Step 2: Understand thread safety
This ensures only one thread modifies counter at a time, preventing race conditions.
Step 3: Check for deadlocks or exceptions
Mutex is properly used and released after each block, so no deadlocks or exceptions occur.
Final Answer:
No issue; the Mutex correctly prevents race conditions. -> Option D
Quick Check:
Mutex ensures safe increments [OK]

Quick Trick: Mutex protects shared data from race conditions [OK]

Common Mistakes:

Assuming Mutex is unnecessary for shared variables
Believing Mutex causes deadlocks without evidence
Thinking Mutex usage always raises exceptions

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More Ruby Quizzes

Examine this Ruby code snippet:

Step 1: Analyze Mutex usage

Step 2: Understand thread safety

Step 3: Check for deadlocks or exceptions

Final Answer:

Quick Check:

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