[Solved] What will be the output of this Ruby code? pid = fork do puts 'Child process' end puts 'Parent process' Process.wait(pid) | Ruby

Ruby - Concurrent Programming

What will be the output of this Ruby code?

pid = fork do
  puts 'Child process'
end
puts 'Parent process'
Process.wait(pid)

AChild process\nParent process

BParent process\nChild process

CChild process only

DParent process only

Step-by-Step Solution

Solution:

Step 1: Understand execution order after fork
The parent prints 'Parent process' immediately after fork. The child prints 'Child process' inside the fork block.
Step 2: Analyze Process.wait effect
Process.wait(pid) makes parent wait for child to finish, but parent's puts runs before waiting.
Final Answer:
Parent process\nChild process -> Option B
Quick Check:
Output order = parent then child [OK]

Quick Trick: Parent prints before waiting; child prints after fork block [OK]

Common Mistakes:

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