[Solved] What will this Ruby code print?p1 = Proc.new { |x| x * 3 } p2 = Proc.new { |y| y - 4 } p3 = p2 >> p1 puts p3.call(5) | Ruby

Ruby - Functional Patterns in Ruby

What will this Ruby code print?

p1 = Proc.new { |x| x * 3 }
p2 = Proc.new { |y| y - 4 }
p3 = p2 >> p1
puts p3.call(5)

A3

B33

C15

D11

Step-by-Step Solution

Solution:

Step 1: Understand composition order
p3 = p2 >> p1 means p3.call(x) = p1.call(p2.call(x)).
Step 2: Calculate output for input 5
p2.call(5) = 5 - 4 = 1, then p1.call(1) = 1 * 3 = 3.
Step 3: Re-check order
Wait, the code says p3 = p2 >> p1, so first p2, then p1. So output is 3.
Final Answer:
3 -> Option A
Quick Check:
p3.call(5) = 3 [OK]

Quick Trick: Composition applies left Proc first, then right [OK]

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