[Solved] What will be the output of this Ruby code?p1 = Proc.new { |n| n * 4 } p2 = Proc.new { |m| m - 1 } p3 = p1 >> p2 puts p3.call(2) | Ruby

Ruby - Functional Patterns in Ruby

What will be the output of this Ruby code?

p1 = Proc.new { |n| n * 4 }
p2 = Proc.new { |m| m - 1 }
p3 = p1 >> p2
puts p3.call(2)

A8

B7

C6

D9

Step-by-Step Solution

Solution:

Quick Trick: Evaluate left Proc first, then right [OK]

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