[Solved] Why does composing Procs with the > in Ruby? — Ans: << composes Procs in reverse order, applying right Proc first | Ruby

Ruby - Functional Patterns in Ruby

Why does composing Procs with the << operator produce different results than using >> in Ruby?

A<< causes syntax error when used with Procs

B<< is an alias for >> and behaves the same

C<< merges Procs into an array instead of composing

D<< composes Procs in reverse order, applying right Proc first

Step-by-Step Solution

Solution:

Step 1: Understand << and >> operators for Procs
>> applies left Proc then right; << applies right Proc then left.
Step 2: Explain effect on composition order
p1 << p2 means p1.call(p2.call(x)), reversing order.
Final Answer:
<< composes Procs in reverse order, applying right Proc first -> Option D
Quick Check:
<< reverses Proc composition order [OK]

Quick Trick: << reverses composition order vs >> [OK]

Common Mistakes:

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