Ruby - Functional Patterns in Ruby
What will be the output of this Ruby code using the pipeline operator?
def triple(x)
x * 3
end
def decrement(x)
x - 1
end
result = 2 |> triple |> decrement |> triple
puts resultWhat will be the output of this Ruby code using the pipeline operator?
hard📝 Application Q8 of 15
Step-by-Step Solution
Solution:
Step 1: Evaluate
Calling2 |> tripletriple(2)returns2 * 3 = 6.Step 2: Evaluate
Calling6 |> decrementdecrement(6)returns6 - 1 = 5.Step 3: Evaluate
Calling5 |> tripletriple(5)returns5 * 3 = 15.Final Answer:
15 -> Option AQuick Check:
Calculate stepwise and verify final output [OK]
Quick Trick: Evaluate pipeline step-by-step left to right [OK]
Common Mistakes:
- Applying methods in wrong order
- Miscomputing intermediate results
- Confusing decrement with decrementing by 2
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