[Solved] What is the output of the following Ruby code?def square(x) x * x end def increment(x) x + 1 end result = 3 |> square |> increment puts result | Ruby

Ruby - Functional Patterns in Ruby

What is the output of the following Ruby code?

def square(x)
  x * x
end

def increment(x)
  x + 1
end

result = 3 |> square |> increment
puts result

A16

B10

C9

D7

Step-by-Step Solution

Solution:

Step 1: Evaluate the first pipeline step
Start with 3, pass to square: 3 * 3 = 9.
Step 2: Evaluate the second pipeline step
Pass 9 to increment: 9 + 1 = 10.
Final Answer:
10 -> Option B
Quick Check:
Pipeline output = 10 [OK]

Quick Trick: Calculate step-by-step left to right through pipeline [OK]

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