[Solved] What is the output of this Ruby code?(1..Float::INFINITY).lazy.select { |x| x % 3 == 0 }.first(5) — Ans: [3, 6, 9, 12, 15] | Ruby

Ruby - Functional Patterns in Ruby

What is the output of this Ruby code?

(1..Float::INFINITY).lazy.select { |x| x % 3 == 0 }.first(5)

ARuntime error due to infinite range

B[3, 6, 9, 12, 15]

C[0, 3, 6, 9, 12]

D[1, 2, 3, 4, 5]

Step-by-Step Solution

Solution:

Step 1: Understand lazy filtering on infinite range
The code lazily selects numbers divisible by 3 from 1 to infinity, then takes the first 5 such numbers.
Step 2: Identify the first 5 multiples of 3 starting from 1
These are 3, 6, 9, 12, and 15.
Final Answer:
[3, 6, 9, 12, 15] -> Option B
Quick Check:
Lazy select multiples of 3 first 5 = [3, 6, 9, 12, 15] [OK]

Quick Trick: Lazy enumerators handle infinite ranges safely [OK]

Common Mistakes:

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