[Solved] What will be printed by this Ruby code involving two Fibers exchanging values?fiber_a = Fiber.new do val = Fiber.yield 10 puts "Fiber A got: #{val}" end fiber_b = Fiber.new do x = fiber_a.... | Ruby

Ruby - Concurrent Programming

What will be printed by this Ruby code involving two Fibers exchanging values?

fiber_a = Fiber.new do
  val = Fiber.yield 10
  puts "Fiber A got: #{val}"
end

fiber_b = Fiber.new do
  x = fiber_a.resume
  Fiber.yield x + 5
  fiber_a.resume 20
end

puts fiber_b.resume
puts fiber_b.resume

AFiber A got: 20 10 15

B10 Fiber A got: 20 15

C10 15 Fiber A got: 20

D15 10 Fiber A got: 20

Step-by-Step Solution

Solution:

Step 1: First resume fiber_b
fiber_b resumes fiber_a, which yields 10, so fiber_b.resume returns 10.
Step 2: fiber_b yields 10 + 5 = 15
Second resume of fiber_b returns 15.
Step 3: fiber_b resumes fiber_a with 20
fiber_a receives 20 and prints "Fiber A got: 20".
Final Answer:
10 15 Fiber A got: 20 -> Option C
Quick Check:
Track yields and resumes carefully [OK]

Quick Trick: Follow resume and yield values step-by-step [OK]

Common Mistakes:

Mixing order of printed values
Forgetting that Fiber.yield returns control to caller

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What will be printed by this Ruby code involving two Fibers exchanging values?

Step 1: First resume fiber_b

Step 2: fiber_b yields 10 + 5 = 15

Step 3: fiber_b resumes fiber_a with 20

Final Answer:

Quick Check:

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