Given a curried lambda calc = ->(a, b, c) { a * c + b }.curry, how do you create a new function that multiplies by 10 and adds 5?

hard📝 Application Q9 of 15

Ruby - Functional Patterns in Ruby

Given a curried lambda calc = ->(a, b, c) { a * c + b }.curry, how do you create a new function that multiplies by 10 and adds 5?

Anew_func = calc.call(10).call(5).call(1)

Bnew_func = calc.call(10).call(1).call(5)

Cnew_func = calc.call(10).call(5)

Dnew_func = calc.call(10).call(0).call(5)

Step-by-Step Solution

Solution:

Step 1: Understand the lambda parameters
The lambda calculates a * c + b. To create a new function that multiplies its input by 10 and adds 5, fix a=10 (multiplier) and b=5 (addend).
Step 2: Apply arguments in order
Calling calc.call(10) fixes a, then call(5) fixes b, returning a new function f(c) { 10 * c + 5 }.
Final Answer:
new_func = calc.call(10).call(5) -> Option C
Quick Check:
Correct argument order fixes function [OK]

Quick Trick: Apply arguments in lambda parameter order [OK]

Common Mistakes:

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