[Solved] What is the issue with this Ruby code?divide = ->(x, y) { x / y } curried_divide = divide.curry result = curried_divide.call(10, 2) puts result | Ruby

Ruby - Functional Patterns in Ruby

What is the issue with this Ruby code?

divide = ->(x, y) { x / y }
curried_divide = divide.curry
result = curried_divide.call(10, 2)
puts result

AIt raises an ArgumentError because too many arguments are passed to curried function

BIt outputs 5 correctly

CIt raises a ZeroDivisionError

DIt outputs 0

Step-by-Step Solution

Solution:

Step 1: Define the lambda
The lambda divides x by y.
Step 2: Curry the lambda
Currying expects arguments one at a time.
Step 3: Incorrect call with two arguments
curried_divide.call(10, 2) passes both arguments at once, which is invalid for curried procs.
Step 4: Correct usage
Should call as curried_divide.call(10).call(2).
Final Answer:
It raises an ArgumentError because too many arguments are passed to curried function -> Option A
Quick Check:
Curried procs accept one argument per call [OK]

Quick Trick: Curried functions require one argument per call [OK]

Common Mistakes:

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