[Solved] What will be the output of this Ruby code?subtract = ->(a, b) { a - b } curried_subtract = subtract.curry subtract_from_ten = curried_subtract.call(10) puts subtract_from_ten.call(4) | Ruby

Ruby - Functional Patterns in Ruby

What will be the output of this Ruby code?

subtract = ->(a, b) { a - b }
curried_subtract = subtract.curry
subtract_from_ten = curried_subtract.call(10)
puts subtract_from_ten.call(4)

AError

B14

C-6

D6

Step-by-Step Solution

Solution:

Step 1: Define the lambda
The lambda subtracts the second argument from the first: a - b.
Step 2: Curry the lambda
Using subtract.curry allows partial application of arguments.
Step 3: Partially apply first argument
subtract_from_ten = curried_subtract.call(10) fixes a = 10.
Step 4: Call with second argument
subtract_from_ten.call(4) computes 10 - 4 = 6.
Final Answer:
6 -> Option D
Quick Check:
10 minus 4 equals 6 [OK]

Quick Trick: Currying fixes arguments one at a time [OK]

Common Mistakes:

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