[Solved] What will be the output of this Ruby code?class Animal protected def sound "growl" end def call_sound(other) other.sound end end lion = Animal.new wolf = Animal.new puts lion.call_sound(wolf) | Ruby

Ruby - Inheritance

What will be the output of this Ruby code?

class Animal
  protected
  def sound
    "growl"
  end

  def call_sound(other)
    other.sound
  end
end

lion = Animal.new
wolf = Animal.new
puts lion.call_sound(wolf)

Agrowl

BNoMethodError

Cnil

DArgumentError

Step-by-Step Solution

Solution:

Step 1: Understand protected method call
The method sound is protected, so it can be called by instances of the same class on each other.
Step 2: Trace the call
lion.call_sound(wolf) calls wolf.sound inside the class, which is allowed and returns "growl".
Final Answer:
growl -> Option A
Quick Check:
Protected method call between instances = growl [OK]

Quick Trick: Protected methods callable between instances of same class [OK]

Common Mistakes:

Expecting NoMethodError due to protected method
Thinking protected methods are private and inaccessible
Assuming method returns nil instead of string

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More Ruby Quizzes

What will be the output of this Ruby code?

Step 1: Understand protected method call

Step 2: Trace the call

Final Answer:

Quick Check:

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