[Solved] What will be the output of this Ruby code?class Person protected def secret "protected info" end public def reveal_secret(other) other.secret end end p1 = Person.new p2 = Person.new puts p1.... | Ruby

Ruby - Inheritance

What will be the output of this Ruby code?

class Person
  protected
  def secret
    "protected info"
  end

  public
  def reveal_secret(other)
    other.secret
  end
end

p1 = Person.new
p2 = Person.new
puts p1.reveal_secret(p2)

ASyntaxError

BNoMethodError: protected method `secret' called

Cprotected info

Dnil

Step-by-Step Solution

Solution:

Step 1: Understand protected method access
Protected methods can be called by other instances of the same class. Here, p1 calls reveal_secret passing p2, and inside it calls other.secret.
Step 2: Predict output
Since secret is protected, p1 can call secret on p2. The method returns "protected info", which is printed.
Final Answer:
protected info -> Option C
Quick Check:
Protected allows calls between same class instances [OK]

Quick Trick: Protected allows access between same class instances [OK]

Common Mistakes:

Thinking protected methods can't be called on other instances
Expecting NoMethodError for protected method call
Confusing protected with private access

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What will be the output of this Ruby code?

Step 1: Understand protected method access

Step 2: Predict output

Final Answer:

Quick Check:

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