[Solved] Given this code, what will be the output? def create_proc Proc.new { |x| x.nil? ? 'No value' : x * 10 } end my_proc = create_proc puts my_proc.call(nil) puts my_proc.call(5) | Ruby

Ruby - Blocks, Procs, and Lambdas

Given this code, what will be the output?

def create_proc
  Proc.new { |x| x.nil? ? 'No value' : x * 10 }
end

my_proc = create_proc
puts my_proc.call(nil)
puts my_proc.call(5)

Anil\n50

BError\n50

CNo value\n50

DNo value\n5

Step-by-Step Solution

Solution:

Step 1: Analyze the Proc logic and trace both calls
The Proc checks if x is nil; if yes, returns 'No value', else returns x * 10. Calling with nil returns 'No value'. Calling with 5 returns 5 * 10 = 50.
Final Answer:
No value\n50 -> Option C
Quick Check:
nil -> 'No value', 5 -> 50 [OK]

Quick Trick: Proc can handle nil with conditional inside block [OK]

Common Mistakes:

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