[Solved] You want to update multiple characters in a Ruby string efficiently. Which approach best uses string mutability? str = "hello" # Update 'e' and 'o' to 'a' and 'u' | Ruby

Ruby - String Operations

You want to update multiple characters in a Ruby string efficiently. Which approach best uses string mutability?

str = "hello"
# Update 'e' and 'o' to 'a' and 'u'

Astr.freeze; str[1] = 'a'

Bstr = str.sub('e', 'a').sub('o', 'u')

Cstr = "hallu"

Dstr[1] = 'a'; str[4] = 'u'

Step-by-Step Solution

Solution:

Step 1: Identify direct string mutation
str[1] = 'a'; str[4] = 'u' changes characters by index directly, using mutability efficiently without creating new strings.
Step 2: Compare other options
str = str.sub('e', 'a').sub('o', 'u') creates new strings with sub; str = "hallu" assigns a new string; str.freeze; str[1] = 'a' freezes string then tries to change causing error.
Final Answer:
str[1] = 'a'; str[4] = 'u' -> Option D
Quick Check:
Direct index assignment updates string efficiently [OK]

Quick Trick: Change characters by index for efficient updates [OK]

Common Mistakes:

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