[Solved] The following Ruby code is intended to print "Falsy" only when var is falsy. What is wrong? var = nil if var == false puts "Falsy" else puts "Truthy" end | Ruby

Ruby - Operators and Expressions

The following Ruby code is intended to print "Falsy" only when var is falsy. What is wrong?

var = nil
if var == false
  puts "Falsy"
else
  puts "Truthy"
end

AIt should check 'if var == nil' only

BSyntax error in the if statement

CIt misses the case when var is nil, which is also falsy

DIt should use 'var != false' instead

Step-by-Step Solution

Solution:

Step 1: Understand falsy values in Ruby
Both false and nil are falsy in Ruby.
Step 2: Analyze the condition
The code checks only var == false, so it misses nil which is also falsy.
Final Answer:
It misses the case when var is nil, which is also falsy -> Option C
Quick Check:
Falsy = false or nil [OK]

Quick Trick: Check both false and nil for falsy, not just false [OK]

Common Mistakes:

Master "Operators and Expressions" in Ruby

9 interactive learning modes - each teaches the same concept differently

More Ruby Quizzes

The following Ruby code is intended to print "Falsy" only when var is falsy. What is wrong?