Given n = 3, which code snippet correctly prints the numbers 1 to n using times?

hard📝 Application Q9 of 15

Ruby - Loops and Iteration

Given n = 3, which code snippet correctly prints the numbers 1 to n using times?

A(1..n).times { |i| puts i }

Bn.times { |i| puts i }

Cn.times { |i| puts i + 1 }

Dn.times { puts i + 1 }

Step-by-Step Solution

Solution:

Step 1: Understand times block variable range
Block variable i runs from 0 to n-1.
Step 2: Adjust output to print 1 to n
Adding 1 to i prints numbers 1 through n.
Final Answer:
n.times { |i| puts i + 1 } -> Option C
Quick Check:
Print 1 to n by adding 1 to i [OK]

Quick Trick: Add 1 to block variable to start from 1 [OK]

Common Mistakes:

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