Given str = "abracadabra", which code extracts every second character starting from index 0 to index 8 (inclusive)?

hard📝 Application Q15 of 15

Ruby - String Operations

Given str = "abracadabra", which code extracts every second character starting from index 0 to index 8 (inclusive)?

Astr[0..8][::2]

Bstr[0..8].chars.select.with_index { |_, i| i.even? }.join

Cstr[0, 8, 2]

Dstr[0..8].chars.each_slice(2).map(&:first).join

Step-by-Step Solution

Solution:

Step 1: Understand Ruby slicing limitations
Ruby's slice method does not support step values like Python. So str[0, 8, 2] or str[0..8][::2] are invalid.
Step 2: Use chars with index filtering to pick every second character
str[0..8] gets substring 'abracadab'. Then chars.select.with_index { |_, i| i.even? } picks characters at even indices: a (0), r (2), c (4), d (6), b (8). Joining gives 'ar cdb' without spaces: 'arcdb'.
Final Answer:
str[0..8].chars.select.with_index { |_, i| i.even? }.join -> Option B
Quick Check:
Use chars and select.with_index for stepping [OK]

Quick Trick: Ruby slice has no step; use chars with index filtering [OK]

Common Mistakes:

MISTAKES

Master "String Operations" in Ruby

9 interactive learning modes - each teaches the same concept differently

Want More Practice?

15+ quiz questions · All difficulty levels · Free

More Ruby Quizzes