[Solved] Why does str[5..3] return nil in Ruby when str = "example"? — Ans: Because the range start is greater than end, resulting in nil | Ruby

Ruby - String Operations

Why does str[5..3] return nil in Ruby when str = "example"?

ABecause it returns an empty string, not nil

BBecause indices 5 and 3 are out of string bounds

CBecause Ruby does not support range slicing

DBecause the range start is greater than end, resulting in nil

Step-by-Step Solution

Solution:

Step 1: Understand range slicing behavior
In Ruby, range start must be less than or equal to end for slicing.
Step 2: Check given range 5..3
Since 5 > 3, the range is invalid and returns nil.
Final Answer:
Because the range start is greater than end, resulting in nil -> Option D
Quick Check:
Invalid range start > end returns nil [OK]

Quick Trick: Range start must be ≤ end for slicing [OK]

Common Mistakes:

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Why does str[5..3] return nil in Ruby when str = "example"?