You have a list of names with extra spaces and mixed cases: [" Alice", "bob ", "CHARLIE"]. Which Ruby code correctly returns a new list with all names trimmed and in uppercase?

hard📝 Application Q8 of 15

Ruby - String Operations

You have a list of names with extra spaces and mixed cases: [" Alice", "bob ", "CHARLIE"]. Which Ruby code correctly returns a new list with all names trimmed and in uppercase?

A[" Alice", "bob ", "CHARLIE"].map { |n| n.strip.upcase }

B[" Alice", "bob ", "CHARLIE"].map { |n| n.upcase }

C[" Alice", "bob ", "CHARLIE"].map(&:strip).map(&:downcase)

D[" Alice", "bob ", "CHARLIE"].map(&:upcase)

Step-by-Step Solution

Solution:

Step 1: Understand the order of methods
We must remove spaces first with strip, then convert to uppercase with upcase.
Step 2: Analyze each option
[" Alice", "bob ", "CHARLIE"].map { |n| n.strip.upcase } correctly strips spaces then upcases each name. [" Alice", "bob ", "CHARLIE"].map { |n| n.upcase } upcases first, leaving spaces. [" Alice", "bob ", "CHARLIE"].map(&:strip).map(&:downcase) strips then downcases (wrong case). [" Alice", "bob ", "CHARLIE"].map(&:upcase) upcases, leaving spaces.
Final Answer:
[" Alice", "bob ", "CHARLIE"].map { |n| n.strip.upcase } -> Option A
Quick Check:
strip then upcase in map = clean uppercase list [OK]

Quick Trick: Strip spaces before changing case for clean results [OK]

Common Mistakes:

Changing case before stripping spaces
Using multiple map calls unnecessarily
Assuming order doesn't matter

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More Ruby Quizzes

You have a list of names with extra spaces and mixed cases: [" Alice", "bob ", "CHARLIE"]. Which Ruby code correctly returns a new list with all names trimmed and in uppercase?

Step 1: Understand the order of methods

Step 2: Analyze each option

Final Answer:

Quick Check:

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