Ruby - Methods
What is the output of this Ruby code?
def multiply(x, y = 2) x * y end puts multiply(4) puts multiply(4, 3)
What is the output of this Ruby code?
medium📝 Predict Output Q13 of 15
Step-by-Step Solution
Solution:
Step 1: Analyze method calls with default parameter
First call:multiply(4)uses default y=2, so 4*2=8. Second call:multiply(4,3)uses y=3, so 4*3=12.Step 2: Determine output of puts statements
Outputs are printed on separate lines: 8 then 12.Final Answer:
8 12 -> Option AQuick Check:
Default param used when missing = 8, explicit param = 12 [OK]
Quick Trick: Default used if argument missing, else given value [OK]
Common Mistakes:
MISTAKES- Expecting error when argument is missing
- Confusing default parameter with keyword arguments
- Mixing up output values
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