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Why does the expression !false && false || true evaluate to true in Ruby?

hard📝 Conceptual Q10 of 15
Ruby - Operators and Expressions
Why does the expression !false && false || true evaluate to true in Ruby?
ABecause && has higher precedence than ||, so !false && false is false, then false || true is true
BBecause || has higher precedence than &&, so false && false || true is true
CBecause !false && false is true, and true || true is true
DBecause !false is false, so false && false || true is true
Step-by-Step Solution
Solution:

  1. Step 1: Understand operator precedence

    In Ruby, && has higher precedence than ||.

  2. Step 2: Evaluate !false && false first

    !false is true, so true && false is false.

  3. Step 3: Evaluate false || true

    false || true is true.

  4. Final Answer:

    The expression evaluates to true due to operator precedence -> Option A

  5. Quick Check:

    && before || changes evaluation order [OK]
Quick Trick: && is evaluated before || in Ruby expressions [OK]
Common Mistakes:
  • Ignoring operator precedence
  • Assuming || evaluated first
  • Misreading !false value

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