[Solved] Given this Ruby code:def add(x, y) x + y end result = add(2, 3) + add(4, 5) print resultHow does Ruby interpret and calculate the final output? | Ruby

Ruby - Basics and Runtime

Given this Ruby code:

def add(x, y)
  x + y
end

result = add(2, 3) + add(4, 5)
print result

How does Ruby interpret and calculate the final output?

AIt prints the string 'add(2, 3)add(4, 5)'

BIt adds 2 and 3, then adds 4 and 5, sums both results to print 14

CIt throws an error because add is called twice

DIt adds 2 and 3, ignores second add call, prints 5

Step-by-Step Solution

Solution:

Quick Trick: Each method call runs fully, then sums results [OK]

Common Mistakes:

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