Solution:Step 1: Check initial value of options[:retries]It is false, which is falsy.Step 2: Apply ||= operatorSince false, options[:retries] ||= 3 assigns 3.Final Answer:3, because false triggers ||= assignment -> Option AQuick Check:False triggers ||= assignment on hash keys [OK]

[Solved] Consider this code:options = { retries: false } options[:retries] ||= 3 puts options[:retries]What will be printed and why? | Ruby

Ruby - Operators and Expressions

Consider this code:

options = { retries: false }
options[:retries] ||= 3
puts options[:retries]

What will be printed and why?

A3, because false triggers ||= assignment

Bfalse, because key exists

Cnil, because false is ignored

DError, because false is invalid for ||= operator

Step-by-Step Solution

Solution:

Step 1: Check initial value of options[:retries]
It is false, which is falsy.
Step 2: Apply ||= operator
Since false, options[:retries] ||= 3 assigns 3.
Final Answer:
3, because false triggers ||= assignment -> Option A
Quick Check:
False triggers ||= assignment on hash keys [OK]

Quick Trick: False triggers ||= assignment even in hashes [OK]

Common Mistakes:

MISTAKES

Assuming existing key prevents assignment
Thinking false is truthy
Expecting error with false value

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Consider this code:

Step 1: Check initial value of options[:retries]

Step 2: Apply ||= operator

Final Answer:

Quick Check:

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