[Solved] Consider this Ruby code:arr = [1, 2, 3, 4] arr.each do |num| if num == 3 redo end puts num endWhat will happen when this code runs? | Ruby

Ruby - Loops and Iteration

Consider this Ruby code:

arr = [1, 2, 3, 4]
arr.each do |num|
  if num == 3
    redo
  end
  puts num
end

What will happen when this code runs?

AIt prints 1, 2, then gets stuck repeating 3 infinitely.

BIt skips printing 3 and continues with 4.

CIt prints 1, 2, 3, 4 normally.

DIt raises a syntax error.

Step-by-Step Solution

Solution:

Step 1: Analyze redo inside each block
When num == 3, redo repeats the current iteration without advancing.
Step 2: Understand loop behavior
This causes infinite repetition of 3, so printing 3 repeats endlessly.
Final Answer:
It prints 1, 2, then gets stuck repeating 3 infinitely. -> Option A
Quick Check:
Redo causes infinite repeat on 3 [OK]

Quick Trick: Redo repeats iteration, watch for infinite loops [OK]

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