[Solved] What will be the output of the following Ruby code? arr = [1, 2, 3] arr.reverse puts arr.inspect arr.reverse! puts arr.inspect | Ruby

Ruby - Methods

What will be the output of the following Ruby code?

arr = [1, 2, 3]
arr.reverse
puts arr.inspect
arr.reverse!
puts arr.inspect

A[1, 2, 3]\n[3, 2, 1]

B[3, 2, 1]\n[1, 2, 3]

C[1, 2, 3]\n[1, 2, 3]

D[3, 2, 1]\n[3, 2, 1]

Step-by-Step Solution

Solution:

Step 1: Understand arr.reverse effect
arr.reverse returns a new reversed array but does not change arr itself, so arr.inspect prints the original: [1, 2, 3].
Step 2: Understand arr.reverse! effect
arr.reverse! reverses arr in place, changing it to [3, 2, 1]. So the second print shows [3, 2, 1].
Final Answer:
[1, 2, 3] [3, 2, 1] -> Option A
Quick Check:
Non-bang no change, bang changes object [OK]

Quick Trick: Non-bang returns new object; bang changes original [OK]

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