[Solved] What will be the output of the following Ruby code?arr = Array.new(3, Hash.new) arr[0][:key] = 'value' puts arr.inspect | Ruby

Ruby - Arrays

What will be the output of the following Ruby code?

arr = Array.new(3, Hash.new)
arr[0][:key] = 'value'
puts arr.inspect

A[{}, {}, {}]

B[{:key=>"value"}, {:key=>"value"}, {:key=>"value"}]

C[{:key=>"value"}, {}, {}]

D[{}, {:key=>"value"}, {}]

Step-by-Step Solution

Solution:

Step 1: Understand Array.new with a shared object
Using Array.new(3, Hash.new) creates an array with 3 references to the same hash object.
Step 2: Modify one element
When arr[0][:key] = 'value' is executed, it modifies the single shared hash object.
Final Answer:
[{:key=>"value"}, {:key=>"value"}, {:key=>"value"}] -> Option B
Quick Check:
All elements point to the same hash, so all show the change. [OK]

Quick Trick: Array.new with object shares same reference [OK]

Common Mistakes:

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