[Solved] You want to implement exponential backoff retry for a REST API call in Python. Which approach correctly applies this?import time for i in range(4): response = requests.get('https://api.example.... | Rest API

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You want to implement exponential backoff retry for a REST API call in Python. Which approach correctly applies this?

import time

for i in range(4):
    response = requests.get('https://api.example.com')
    if response.status_code == 200:
        print('Success')
        break
    else:
        time.sleep(2 ** i)
else:
    print('Failed after retries')

AThis code will cause a syntax error due to else after for

BThis code correctly waits longer after each failed attempt using exponential backoff

CThis code does not retry on failure

DThis code waits the same amount of time after each retry

Step-by-Step Solution

Solution:

Step 1: Understand exponential backoff
Exponential backoff means waiting longer after each failure, here time.sleep(2 ** i) doubles wait time each retry.
Step 2: Check code correctness
Code retries 4 times, breaks on success, else after for runs if loop completes without break, no syntax error.
Final Answer:
This code correctly waits longer after each failed attempt using exponential backoff -> Option B
Quick Check:
Exponential backoff = increasing wait times [OK]

Quick Trick: Use time.sleep(2 ** attempt) for exponential backoff [OK]

Common Mistakes:

MISTAKES

Using fixed sleep time instead of exponential
Misunderstanding else after for loop
Not breaking loop on success

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You want to implement exponential backoff retry for a REST API call in Python. Which approach correctly applies this?

Step 1: Understand exponential backoff

Step 2: Check code correctness

Final Answer:

Quick Check:

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