[Solved] What will be the output of this code?class MyError(Exception): pass def test(value): if value < 0: raise MyError("Negative value") return value try: print(test(-1)) except MyError as e: print(e) | Python

Python - Custom Exceptions

What will be the output of this code?

class MyError(Exception):
    pass

def test(value):
    if value < 0:
        raise MyError("Negative value")
    return value

try:
    print(test(-1))
except MyError as e:
    print(e)

ANegative value

B-1

CNone

DNo output

Step-by-Step Solution

Solution:

Step 1: Analyze function behavior
The function test raises MyError with message "Negative value" if input is less than 0.
Step 2: Trace try-except block
Calling test(-1) raises MyError. The except block catches it and prints the error message.
Final Answer:
Negative value -> Option A
Quick Check:
Raised custom exception message printed [OK]

Quick Trick: Raised custom exception prints its message in except block [OK]

Common Mistakes:

Expecting function to return -1
Thinking no output occurs
Confusing exception name with message

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What will be the output of this code?

Step 1: Analyze function behavior

Step 2: Trace try-except block

Final Answer:

Quick Check:

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