[Solved] What will be the output of this code?def check_positive(num): if num <= 0: raise ValueError('Number must be positive') return num print(check_positive(-5)) | Python

Python - Advanced Exception Handling

What will be the output of this code?

def check_positive(num):
    if num <= 0:
        raise ValueError('Number must be positive')
    return num

print(check_positive(-5))

ANumber must be positive

BNone

C-5

DValueError: Number must be positive

Step-by-Step Solution

Solution:

Step 1: Analyze function behavior with input -5
The function raises a ValueError if the number is not positive.
Step 2: Understand what happens when exception is raised
Since -5 <= 0, the function raises ValueError with the message.
Final Answer:
ValueError: Number must be positive -> Option D
Quick Check:
Exception raised = B [OK]

Quick Trick: Raise stops execution and shows error message [OK]

Common Mistakes:

MISTAKES

Master "Advanced Exception Handling" in Python

9 interactive learning modes - each teaches the same concept differently

More Python Quizzes

What will be the output of this code?