[Solved] What will be the output of this code?class Shape: def area(self): return 0 class Square(Shape): def __init__(self, side): self.side = side def area(self): return self.side * self.... | Python

Python - Polymorphism and Dynamic Behavior

What will be the output of this code?

class Shape:
    def area(self):
        return 0

class Square(Shape):
    def __init__(self, side):
        self.side = side
    def area(self):
        return self.side * self.side

shapes = [Shape(), Square(4)]
for shape in shapes:
    print(shape.area())

A0\n16

B0\n4

CError: missing side attribute

D16\n0

Step-by-Step Solution

Solution:

Step 1: Analyze class methods and objects
Shape.area returns 0; Square overrides area to return side squared.
Step 2: Loop through shapes and call area()
Shape() returns 0; Square(4) returns 4*4=16; prints in order.
Final Answer:
0\n16 -> Option A
Quick Check:
Polymorphism area output = 0 then 16 [OK]

Quick Trick: Subclass method overrides base method output [OK]

Common Mistakes:

Expecting side attribute in base class
Mixing order of outputs
Assuming area returns side, not side squared

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What will be the output of this code?

Step 1: Analyze class methods and objects

Step 2: Loop through shapes and call area()

Final Answer:

Quick Check:

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