[Solved] Identify the issue in this code snippet:class Example: def __init__(self): __value = 50 ex = Example() print(ex.__value) | Python

Python - Encapsulation and Data Protection

Identify the issue in this code snippet:

class Example:
    def __init__(self):
        __value = 50
ex = Example()
print(ex.__value)

AMissing self parameter in __init__

BThe attribute __value is correctly defined and accessible

CThe attribute __value is local to __init__, not an instance attribute

DSyntax error due to double underscores

Step-by-Step Solution

Solution:

Step 1: Check attribute definition
Variable __value inside __init__ without self. is local to the method, not an instance attribute.
Step 2: Accessing instance attribute
Trying to access ex.__value fails because the instance has no such attribute.
Final Answer:
The attribute __value is local to __init__, not an instance attribute -> Option C
Quick Check:
Instance attributes require self. prefix [OK]

Quick Trick: Attributes need self. to be instance variables [OK]

Common Mistakes:

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