[Solved] Given this code, what will be printed?try: d = {'a': 1} print(d['b']) except KeyError: print('KeyError caught') except Exception: print('General exception caught') | Python

Python - Exception Handling Fundamentals

Given this code, what will be printed?

try:
    d = {'a': 1}
    print(d['b'])
except KeyError:
    print('KeyError caught')
except Exception:
    print('General exception caught')

AGeneral exception caught

BBoth messages printed

CNo output, program crashes

DKeyError caught

Step-by-Step Solution

Solution:

Step 1: Identify the exception raised
Accessing d['b'] raises KeyError because 'b' is not a key in the dictionary.
Step 2: Determine which except block runs
KeyError except block matches and runs, printing 'KeyError caught'.
Final Answer:
KeyError caught -> Option D
Quick Check:
Specific KeyError except runs first [OK]

Quick Trick: Specific exception blocks catch matching errors first [OK]

Common Mistakes:

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