[Solved] Identify the error in this code snippet and select the correct fix:try: y = int('xyz') except ValueError, TypeError: print('Exception caught') | Python

Python - Exception Handling Fundamentals

Identify the error in this code snippet and select the correct fix:

try:
    y = int('xyz')
except ValueError, TypeError:
    print('Exception caught')

AReplace <code>except ValueError, TypeError:</code> with <code>except (ValueError, TypeError):</code>

BReplace <code>except ValueError, TypeError:</code> with <code>except ValueError or TypeError:</code>

CRemove the comma and write <code>except ValueError TypeError:</code>

DNo error; code is correct

Step-by-Step Solution

Solution:

Step 1: Understand Exception Syntax
To catch multiple exceptions in one block, use a tuple inside parentheses.
Step 2: Analyze the Code
The code uses a comma without parentheses, which is invalid syntax.
Step 3: Correct Syntax
Use except (ValueError, TypeError): to catch both exceptions.
Final Answer:
Replace except ValueError, TypeError: with except (ValueError, TypeError): is the correct fix.
Quick Check:
Use parentheses for multiple exceptions [OK]

Quick Trick: Use parentheses to catch multiple exceptions [OK]

Common Mistakes:

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