[Solved] What will be the output of this code?try: x = int('abc') except ValueError: print('ValueError caught') except Exception: print('General exception caught') | Python

Python - Exception Handling Fundamentals

What will be the output of this code?

try:
    x = int('abc')
except ValueError:
    print('ValueError caught')
except Exception:
    print('General exception caught')

ANo output, program crashes

BGeneral exception caught

CValueError caught

DBoth messages printed

Step-by-Step Solution

Solution:

Step 1: Identify the exception raised
int('abc') raises a ValueError because 'abc' cannot be converted to int.
Step 2: Determine which except block runs
The first except block matches ValueError, so it runs and prints 'ValueError caught'.
Final Answer:
ValueError caught -> Option C
Quick Check:
Specific except block runs first [OK]

Quick Trick: Specific exceptions catch errors before general ones [OK]

Common Mistakes:

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